Question

if 3 is a solution of 3 X square + K - 1 X + 9 is equal to zero then the value of k is what​

Answer 1

Answer: k=-11

Step-by-step explanation:

3 is a solution of 3x^2+(k-1) x+9=0

Put x=3

3×(3)^2+(k-1) ×3+9=0

27+3k-3+9=0

3k=-33

K= -11

Answer 2

Answer:

k = -11

Note:

★ The possible values of the variable which satisfy the equation are called its roots or solution.

★ If x = a is a root or solution of any equation ,then x = a must satisfy that equation.

Solution:

Here,

The given equation is ;

3x² + (k - 1)x + 9 = 0.

Also,

It is given that , 3 is a solution to the given equation.

Hence,

x = 3 must satisfy the given equation .

Thus,

=> 3•3² + (k-1)•3 + 9 = 0

=> 27 + 3k - 3 + 9 = 0

=> 3k + 33 = 0

=> 3k = -33

=> k = -33/3

=> k = -11

Hence,

The required value of k is (-11)