Question

If 3 is a solution of 3x^2+( k-1)x+9 =0, then k=?

Answer 1

3(3*3)+(k-1)*3+9=0
27+3k-3+9=0
33+3k=0
k=-33/3=-11
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Answer 2

Answer:

$Value \:of\:k = -11$

Step-by-step explanation:

$Given ,3\:is \:a \: solution\\of\:\: Quadratic\: equation:\\ 3x^{2}+(k-1)x+9=0$

$substitute \:x=3 \: in \:the \\ equation,\:we\:get$

$3\times 3^{2}+(k-1)3+9=0$

$\implies 3\times 9+3k-3+9=0$

$\implies 27+3k+6=0$

$\implies 33+3k=0$

Divide each term by 3, we get

$\implies 11+k=0$

$\implies k = -11$

Therefore,

$Value \:of\:k = -11$

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