Question

if - 3 is a zero of( k-1) x2+kx+1,then find the value of k (1)

Answer 1

Given that (-3) is one zero, so

(k - 1)(-3)² + k(-3) + 1 = 0

9k - 9 - 3k + 1 = 0

6k - 8 = 0

6k = 8

k = 4/3

Answer 2

Hey

Here is your answer,

Given that,

-3 is the zero is (k-1)x^2 + kx + 1 = 0

p(x) = (k-1) x^2 + kx + 1

p(-3) = (k-1) (-3)^2 + (-3)k +1
9 (k-1) - 3k + 1 = 0
9k - 9 - 3k + 1 = 0
6k = 8
K = 8/6
k = 4/3

Hope it helps you!