Question

if -3 is a zero of p(x)= x^3-7x^2-7kx+9k , find all the zeroes of f(x)​

Answer 1

ANSWER:

-3^3-7(-3^2)-7k(-3)+9k=0

-27-63-21k+9k=0

-90-12k=0

-90=12k

-90/12=k

-30/4=k

-7.5=k

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