Question

If 3 is a zero of polynomial ()=
2 − 4(2 − 1) − 1, then find the value of .​

Answer 1

Answer:

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Step-by-step explanation:

You have

(x−2)(x2+ax−k)=x3−3x2+4x+2k

Multiplying out:

x3+ax2−kx−2x2−2ax+2k=

x3+(a−2)x2−(k+2a)x+2k=x3−3x2+4x+2k

So, equating terms, 2a+k=−4 , 2−a=3 , and thus a=−1 , k−2=−4 , k=−2

k=−2 .