If 3 is a zero of the polynomal
x² + 26-a
Find 'a'
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0
Answer:
Hi there !!
Here's your answer
Step-by-step explanation:
Here, f(x) = x² + 2x - a
3 is the zero of the polynomial, then f(3) = 0
f(3) = 0
(3²)+2(3)-a= 0
9 + 6 - a= 0
15 - a = 0 .
15 = a.
Now, The polynomial is x² + 2x - 15 .
Factorising the polynomial,
x² + 2x - 15
x² + 5x - 3x - 15
x ( x + 5 ) - 3 ( x + 5 )
( x + 5 ) ( x - 3 )
Therefore , x²+2x-15 = (x+5)(x-3)
Zero of the polynomial : The value of the variable for which polynomial is 0
( x + 5 ) ( x - 3 ) = 0
x = -5 , x = 3 .
Therefore, the other zero is -5 .
Answered by
0
Answer:
a = 35
Step-by-step explanation:
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