If '3' is a zero of the polynomial 2 x 2x a then find 'a'.
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Let p(x)=x2+2x−a
As the zero of this polynomial is 3, we know that p(3)=0.
x2+2x−a=0
Put x=3, we get
(3)2+2(3)−a=0
⇒9+6−a=0
⇒15−a=0
⇒−a=−15
⇒a=15
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