if -3 is a zero of the polynomial x3+ax2-bx +6 and a+b=7.find the value of a and b
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value of a =99 b =72
aryandahiya608:
full solve kro plz
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P (-3)=x^3+ax^2-bx+6
(-3)^3+a (-3)^2-b (-3)+6
-27+9a+3b+6
9a+3b-21-(¡)
Now ,
a+b=7
a=7-b
Now substitute this value in (¡)
9(7-b)+3b-21=0
63-9b+3b-21=0
42-6b=0
-6b=-42
6b=42
b=42/6
b=7
Now a+b=7
a+7=7
a=7-7
a=0
Value of a=0
Value of b=7
Mai waise itna lamba kabhi solve nhi karti but kyunki tum bhi jaat ho aur mai bhi isley maine tumhare lie kardia...
(-3)^3+a (-3)^2-b (-3)+6
-27+9a+3b+6
9a+3b-21-(¡)
Now ,
a+b=7
a=7-b
Now substitute this value in (¡)
9(7-b)+3b-21=0
63-9b+3b-21=0
42-6b=0
-6b=-42
6b=42
b=42/6
b=7
Now a+b=7
a+7=7
a=7-7
a=0
Value of a=0
Value of b=7
Mai waise itna lamba kabhi solve nhi karti but kyunki tum bhi jaat ho aur mai bhi isley maine tumhare lie kardia...
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