Question

If 3 is added to both the numerator and the denominator of a fraction, the resulting fraction is 7/8. Instead if 3 is subtracted from both the numerator and the denominator the resulting fraction is 11/13 find the fraction

Answer 1

Answer:

Step-by-step explanation:let us suppose the numerator be x and the denominator be y of the fraction

So acc to 1st condn

x+3/y+3=7/8

8 (×+3)=7 (y+3)

8x+24=7y+21

8x-7y+3=0 ............1)

Then acc to 2nd condn

x-3/y-3=11/13

13x-39=11y-33

13x-11y-6=0 ...........2)

Now solving eqn 1)and 2) we get

x=25 and y=29

Therefor the required fraction

25/29