Question

If 3 is added to both the numerator and the denominator of a fraction, it
4
becomes. If 1 is subtracted from both the numerator and denominator, it
becomes 5. Find the fraction.
2​

Answer 1

Step-by-step explanation:

$\frac{x + 3}{y + 3} = 4$

$\frac{x - 1}{y - 1} = 5$

4y+12=x+3 ---(1)

5y-5 =x-1 ---(2)

4y-x= -3

5y-x= 4

(-) (+) (-)

_________

-1y =-7

y=7

x value,

28-x=-3

-x=-3-28

x=31

hence the fraction is

$\frac{31}{7}$

Answer 2

Step-by-step explanation:

Let us consider the fraction is x and y

X+3/y+3=4

X+3=4y+12

X=4y+9

X-4y=9 (call it equation 1)

X-1/y-1=5

X-1=5y-5

X=5y-4

X-5y=-4 (call it equation 2)

From equation 1 and 2

X-4y=9

X-5y=-4

(on subtracting equation 1 and 2, we get)

Y=13

From equation 1

X=61

(most important point in this the question is wrong) ❓❓