Question

If -3 is one of the roots of x2+3 (k+2)x-9=0 then k

Answer 1

Answer:k=-2

Step-by-step explanation:

p(x)=x^2+3(k+2)x-9=0

-3 is amore root ofand p(x).

(-3)^2+3k(-3)+3(2)(-3)-9=0

9+3k(-3)-18-9=0

-9k=18

k=-2