Question

if 3 is one of the zeroes of p(x)=3x3-x2-kx-45 then find k
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Answer 1

Answer:

Step-by-step explanation:

given

3 is one of the zeroes of p(x) =3x^3-x^2-kx-45

then P(3) =0

3(3)^3 -(3)^2-k(3)-45=0

3.27 - 9 - 3k -45=0

81-9-45-3k=0

27-3k=0

27=3k

k=27/3

k=9

So the value of k is "9".

Hope this will help you!

Answer 2

Answer:

substitute x with 3

Step-by-step explanation:

3×3^3-3×2-k×3-45=0

3×27-6-3k-45=0

81-6-3k-45=0

30-3k=0

30=3k

k= 30/3

k=10

hope it helps☺️