if 3 is one of the zeroes of polynomial p(x) =x³+3x²+kx-24 then k
Answers
Answered by
10
Answer:
=x³+3x²+kx-24
(3)3 + 3(3)2 + k(3) - 24
27+54 + 3k - 24
57+3k
K=57/3
K=19
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Answered by
2
K = -10 is your answer
Step-by-step explanation:
p(x)= x³+3x² + Kx- 24
g(x)= x-3
this gives x=3 in p(x) = 0
p(3)= 3³+ 3(3)² + 3k - 24
= 27 + 27 + 3k - 24
= 54 - 24 + 3k
= 30 + 3k
= 30 = -3k
k = 30/-3
k = -10
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