If –3 is one of the zeroes of the polynomial (k– 1)x2 + k x + 1, find the value of k.
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hey HERE IS YOUR ANSWER JUST SEE ABOVE
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(K-1)x²+k x +1 =0
(K-1)(-3)2 +(-3×k) +1=0
(K-1)(9) -3k +1=0
9k -9 -3k +1 =0
6k =8
k =4/3
I hope this will help you
-by ABHAY
(K-1)(-3)2 +(-3×k) +1=0
(K-1)(9) -3k +1=0
9k -9 -3k +1 =0
6k =8
k =4/3
I hope this will help you
-by ABHAY
abhi569:
Thanks for choosing a brainlist answer
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