Question

If -3 is one of the zeroes of the polynomial (k-1) x2+ kx +1, find the
value of k.

Answer 1

Answer:

x = -3

(k-1)(-3)2+k(-3)+1=0

(k-1)9-3k+1=0

9k-9-3k+1=0

6k-8=0

6k = 8

k = 8/6 = 4/3