Question

if -3 is one of the zeroes of the polynomial (k-1) x²+kx+1, find the value of x.

Answer 1

HEY........!!! Here is ur answer......☺️☺️☺️

Given that......–3 is the one of the zeroes of the polynomial (k–1) x²+kx+1.....…..(1)

Now, when we will put x = –3 then the solution of the polynomial will be zero.

then, on putting x = –3 in equation (1)

=>(k–1)(–3)²+k(–3)+1 = 0
=>9k–9–3k+1 = 0
=>6k–8 = 0
=>k = 8/6
=>k = 4/3 «««««« Ans.

I hope it will help u.......✌️✌️✌️

Answer 2

Put the value of x=-3
Now,
(k-1) x²+kx+1=0
(K-1)(-3)2+k×-3+1=0
(K-1)×9-3k+1=0
9k-9-3k+1=0
6k-8=0
6k=8
K=8/6
K=4/3.


Hope it helps....