Question

if 3 is one of the zeroes of the polynomial
p(x) = x^3+ 3x^2 + kx- 24
then K=
​

Answer 1

Step-by-step explanation:

$p(x) = {x}^{3} + 3 {x}^{2} + kx - 24$

$x = 3$

${3}^{3} + 3( {3}^{2} ) + k(3) - 24 = 0$

$27 + 27 + 3k - 24 = 0$

$30 + 3k = 0$

$3k = - 30$

$k = - 10$

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Answer 2

Answer:

k=-10

as, by p(x)=3

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