if-3 is one of the zeroes of the quadratic
polynomia (k-1)x2+Kx-3, then the
product of the other two zeroes is.
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Step-by-step explanation:
given polynomial is
( k-1) x²+ kx-3
given one zeros is -3 let other be p
then sum of both zeros
-3+p = -k/ (k-1)
=> p= 3- k/ ( k-1)
= (2k-3)/ ( k-1)..............(1)
again
product of both zeros
-3× p= -3/ (k-1)=> p= 1/(k-1) .........(2)
=> 2k-3= 1. (. from (1) and (2) )
=> k = 2
substituting in polynomial we get
x²+2x-3
hence. product of zeros
= - 3/1= -3
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