Question

If 3 is one of the zeros of p(x)=3x^3-x^2-ax-45 find the a

Answer 1

p(x)=3x³-x²-ax-45

3 is the zero of p(x)

Therefore, p(3)=0

p(3)=3(3)³-(3)²-a(3)-45

= 81-9-3a-45

=27-3a

Now

p(3)=0

=>27-3a=0

=>-3a=-27

=>a=9

Hope it clears your doubt.

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