If -3 is one of the zeros of the polynomial (k-1)x2+kx+1 find the value of k.
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Answered by
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Step-by-step explanation:
(k-1)x2+kx+1= 2k-2+kx+1
We have,
x=-3
putting value of x,
2k-1-3k=0
-1k=-1
therefore , k=1
Answered by
0
Answer:
here is ur answer....
Step-by-step explanation:
(k-1) x²+kx+1
= 2k -2 +kx +1
we have,
x= -3
now, putting value of x,
2k-1-3k = 0
= -1k = -1
therefore k=1 ans
hope it will help you,plz mark me as branliest.....
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