Question

If -3 is one of the zeros of the polynomial (x-1)x^2+kx+1 find the value of k

Answer 1

Hey

Here is your answer,

Substitute -3 in places of x,

x^2 + kx +1=0
(-3)^2 + (-3)k +1=0
9-3k+1=0
10-3k=0
10=3k
k=10/3

Hope it helps you!

Answer 2

Step-by-step explanation:

GIVEN:-)

→ One zeros of quadratic polynomial = -3.

→ Quadratic polynomial = ( k - 1 )x² + kx + 1.

Solution:-

→ P(x) = ( k -1 )x² + kx + 1 = 0.

→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.

=> ( k - 1 ) × 9 -3k + 1 = 0.

=> 9k - 9 -3k + 1 = 0.

=> 6k - 8 = 0.

=> 6k = 8.

$\large \boxed{=> k = \frac{8}{6} = \frac{4}{3} }$

Hence, the value of ‘k’ is founded .