Question

if 3 is root of x^2+kx-24=0 it is also a root of​

Answer 1

Answer:

x 2 −kx+6=0

Step-by-step explanation:

x

2

+kx−24=0...(i)

It is given that x=3 satisfies the equation.

Hence

9+3k−24=0

3k=24−9

3k=15

k=5

Thus the equation is

x

2

+5x−24=0

(x+8)(x−3)=0

Hence the roots are x=−8,3.

Now k=5.

Hence an equation of the form

x

2

−kx+d=0 is

x

2

−5x+d=0.

It is given that x=3 satisfies that equation.

Hence

9−15+d=0

d=6.

Thus one possible equation is

x

2

−5x+6=0

Or

x

2

−kx+6=0