Question

if 3 is the root of 3x2xpx-6=0 and the equation p(x2-x)+q=0 has equal roots find p and q

Answer 1

Answer:

p= -7  q= 42

Step-by-step explanation:

3x^2 + px -6=0

3(3)^2 + p(3) -6=0

27 +3p -6+0

21+3p=0

p= -7

p(x^2-x) + q=0

(-7){(3)^2 + (3)} + q=0

(-7)(9-3) + q=0

-42 + q+0

q=42

hope it helps :)