if 3 is the root of the quadratic mission 3 x square - 2 x minus 6 is equal to zero and the quadratic question p x square - 6 + 2 is equal to zero is equal to 10 find the value of P and Q
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(x)=3x^2-px–6=0 ,. ( x)=px^2-px+q=0
(3)=3×(3)^2-3p-6=0, (3)=9p-3p+q=0
27-6+-3p=0. ,. 6p+q=0
-3p+21=0×2.......A
6p+q..........B
now adding AandB
-6p+42=0
6p+q=0
=42+q=0
q=-42
putting B =>6p+(-42)=0
6p=42
p=42/6 => p=7
(3)=3×(3)^2-3p-6=0, (3)=9p-3p+q=0
27-6+-3p=0. ,. 6p+q=0
-3p+21=0×2.......A
6p+q..........B
now adding AandB
-6p+42=0
6p+q=0
=42+q=0
q=-42
putting B =>6p+(-42)=0
6p=42
p=42/6 => p=7
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