Question

If -3 is the zero of (k-1)x² + kx + 1.

Find the value of k

Answer 1

zero = -3

by putting -3 in place of x, we get

(k-1)-3² + k (-3) + 1 = 0

(k-1)9 -3k + 1 = 0

9k-9 - 3k+1 = 0

6k -8 = 0

k = 8/6

= 4/3

Answer 2

Hi !

p(x) = (k-1)x² + kx + 1.

p(-3) = 0

x = -3

Putting this value of  x in p(x)
(k-1)x² + kx + 1 = 0
(k-1)*(-3)² + k*-3 + 1 = 0
9(k-1) - 3k + 1 = 0
9k - 9 - 3k + 1 = 0
6k -8 = 0
6k = 8
k = 8/6
k = 4/3

Value of k is 4/3