Question

if 3 is the zero of the polynomial 2x^2-6k+6, find the value of k​

Answer 1

Answer:

2(3)^2-6k+6=0

18-6k+6=0

24-6k=0

6k=24

k=4

Answer 2

Answer:

K = 4

Step-by-step explanation:

Given, 3 is the zero of the polynomial $(2x)^{2}$ - 6k + 6.

Let f(x) =  $(2x)^{2}$ - 6k + 6. S0, f(3) = 0.

∴ f(3) =  $2(3)^{2}$ - 6k + 6 = 0

⇒ 18 - 6k + 6 = 0  ⇒ 6k = 24

∴ k = 4.

Hence, the value of k is 4.

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