if 3 is the zero of the polynomial x²+2x-a find a
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1 .Let p(x)=x
2
+2x−a
As the zero of this polynomial is 3, we know that p(3)=0.
x
2
+2x−a=0
Put x=3, we get
(3)
2
+2(3)−a=0
⇒9+6−a=0
⇒15−a=0
⇒−a=−15
⇒a=15
2. Now, The polynomial is x² + 2x - 15 . x = -5 , x = 3 . Therefore, the other zero is -5 . If 3 is the zero of p(x) , then p(3) = 0.
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