Question

If 3 is the zero of the polynonial p(x)=2x^2+3x+7a then find the value of a

Answer 1

this is your answer
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Answer 2

The value of a will be "-27/7".

Step-by-step explanation:

$The \ given \ equation \ is:\\2x^2+3x+7a=0\\If \ "3" \ is \ the \ zero \ of \ the \ polynomial,then\\x=3\\On \ putting \ the \ value \ of \ x \ in \ the \ above \ equation,then\\2(3)^2+3(3)+7a=0\\2(9)+3(3)+7a=0\\18+9+7a=0\\27+7a=0\\7a=-27\\a=-\frac{27}{7}$

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