if 3+k,18-k,5k+1 are in A.P, then find k
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Given:
• 3 + k , 18 - k and 5k + 1 are in AP .
To find :
• The value of K .
Solution :
• As we know that, In AP common difference is same :
• b - a = c - b
=> 2b = a + c
Here ,
• a = 3 + k
• b = 18 - k
• c = 5k + 1
=> 2 ( 18 - k ) = 3 + k + 5k + 1.
=> 36 - 2k = 4 + 6k
=> 36 - 4 = 6k + 2k
=> 32 = 8k
=> k = 32/8
=> k = 4
Hence , the value of k is 4.
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