if 3 kg of sugar contains 9*10^8 crystals then how many sugar crystals are there in 4 kg of sugar
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Answers
Answer:
Step -by-step explanation:
Let the no. Of crystals be x
The amount of sugar in kg -3 4
Number of crystals - 9×10^8 ×
So, this two quantities are in directly proportional
Therefore
X1/y1 = x2/y2
= 3/9×10^8 = 4/x
=3×x =4×9×10^8
Therefore,
X=4×9×10^8/3 =12×10^8 = 1.2×10^9
So, the answer is 12×10^8 or 1.2×10^9
No.of crystals are there in 4 kg is 1.2×10^9
Concept:
An equation known as proportion shows that the two ratios presented are equal to one another. In other terms, the proportion declares that the two ratios or fractions are equal. In terms of proportion, two sets of supplied numbers are said to be directly proportional if they increase or decrease in the same ratio.
For instance, the time it takes a train to travel 100 kilometres per hour is equal to the time it needs to travel 500 kilometres in five hours. Example: 100 km/hr = 500 km/5 hour.
It is said that ratio and proportion are two sides of the same coin. Two ratios are said to be in proportion when their values are the same. In simple words it compares two ratios. It can be represented by
a:b::c:d or a:b=c:d or a/b=c/d
Given:
3 kg of sugar contains 9*10^8 crystals
Find:
how many sugar crystals are there in 4 kg of sugar
Solution:
Let the no. Of crystals be x
The amount of sugar in kg = 3
Number of crystals - 9×10⁸
So, this two quantities are in directly proportional
Therefore
X1/y1 = x2/y2
= 3/9×10⁸ = 4/x
=3×x =4×9×10⁸
Therefore,
X=4×9×10⁸/3 =12×10⁸ = 1.2×10⁹
So, the answer is 12×10⁸ or 1.2×10⁹
Therefore,the no.of crystals are there in 4 kg is 1.2×10⁹
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