Question

If 3 L of NH3(g) reacts with 1.2 L of HCl(g) then volume
of gaseous mixture after reaction will be
NH3(g) + HCl(g) – NH4Cl (solid)
a 1.8 L
b 0.8 L
c 1.2 L
d 1.5 L​

Answer 1

HCl (g)+ NH

3

(g) → NH

4

Cl (s)

The chemical reaction is the balanced reaction. Then 3 mole of HCl and ammonia when react they formed 3 moles of ammonium chloride.

Ans is A

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Answer 2

The correct answer is option (a) 1.8 L

GIVEN

Amount of NH₃ gas = 3L

Amount of HCl = 1.2 L

TO FIND

Amount of gaseous mixture left after the reaction.

SOLUTION

We Can simply solve the above problem as follows -

The reaction between NH₃ and HCl can be represented as -

NH₃ + HCl --------> NH₄Cl

since, the equation is balanced, equal moles of HCl and NH₃ will react with each other to given equal moles of NH₄Cl

Amount of NH₃ given = 3L

Amount of HCl given = 1.2 L

Since, The amount of HCl is less, HCl is the limiting reagent.

So, All of HCl gas will be used up.

Amount of NH₃ used = 1.2 L

Amount of NH₃ left = 3-1.2 = 1.8L

Hence, The correct answer is option (a) 1.8 L

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