if 3(log 5-log 3)-(log5-2log6)=2-logx find x
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or 3(log5/3)-(log5/36)=2-logx
or log125/27-log5/36=2-logx
or log(125/27)*(36/5)=2-logx
or log100/3=2-logx
or log100/3+logx=2
or log100x/3=2log10
or 100x/3=100
or x=3......................(ans)
or log125/27-log5/36=2-logx
or log(125/27)*(36/5)=2-logx
or log100/3=2-logx
or log100/3+logx=2
or log100x/3=2log10
or 100x/3=100
or x=3......................(ans)
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