If 3^( log tan x)+3^( log cot x)=2 then x is -
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It has given that, 3^(log tanx) + 3^(log cotx) = 2
We have to find the value of x.
solution : here 3^(log tanx) + 3^(log cotx) = 2
We know, cotx = 1/tanx
so, log cotx = log (1/tanx) = log(tanx)¯¹ = -log tanx
So, 3^(log tanx) + 3^(-log tanx) = 2
⇒3^(log tanx) + 1/3^(log tanx) = 2
let 3^(log tanx) = p
So, p + 1/p = 2
⇒p² - 2p + 1 = 0
⇒p = 1
So, 3^(log tanx) = 1 = 3^0
⇒log tanx = 0
⇒tanx = 1
x = nπ + π/4
For log to be defined , tanx > 0
So, x = -3π/4, π/4, 5π/4, 9π/4 ...
i.e., x = nπ - 3π/4 , where n is integer.
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