Question

if 3^log x to the base 9 =2​

Answer 1

Answer:

${3}^{ log_{9}(x) } = 2 \\ {3}^{ log_{ {3}^{2} }(x) } = 2 \\ {3}^{ \frac{1}{2} log_{3}(x) } = 2 \\ {3}^{ log_{3}( {x}^{ \frac{1}{2} } ) } = 2 \\ {x}^{ \frac{1}{2} } = 2 \\ x = {2}^{2} = 4$