If 3 man and 4 women finish their work in 8 days and 5 man and 6 women finish their work in 5 days. Find that only 1 man will take how many days.
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Gɪᴠᴇɴ :-
- 3 man and 4 women finish their work in 8 days.
- 5 man and 6 women finish their work in 5 days.
Tᴏ Fɪɴᴅ :-
- Find that only 1 man will take how many days. ?
Sᴏʟᴜᴛɪᴏɴ :-
since work is same in Both case ,
→ 8(3M + 4W) = 5(5M + 6W)
→ 24M + 32W = 25M + 30W
→ 25M - 24M = 32W - 30W
→ M = 2W
→ (M/W) = (2/1)
So, Efficiency of M : W = 2 : 1 .
Therefore ,,
→ Total work = 8(3*2 + 4*1) = 8(6 + 4) = 8*10 = 80 units.
Hence,
→ Total work done by 1 Man alone in = (80/2) = 40 Days. (Ans.)
∴ Only 1 Man will take 40 Days to complete the whole work.
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Perfect. ❤️
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