Question

If 3 men and 5 women can do a piece of work
in 8 days and 2 men and 7 boys can do the
same work in 12 days. Find the number of
boys, the work done by whom can equate the workdone by the 10 women.​

Answer 1

$\huge{\boxed{\mathfrak{\overbrace{\underbrace{\fcolorbox{r}{pink}{✯Answer}}}}}}$

(2M+3W)×10=(3M+2W)×8

After solving

We get, 2M=7W

MW=72

Total work=(2×7+3×+)×10

=20×10

=200 units

eff. of 2M+1W=2×7+2=16

∴number of days=20016=252

=1212 Days