If 3 men or 6 boys can do a piece of work in 10 days, working 7 hours a day; how many days will it take to compete a piece of work twice as large with 6 men and 2 boys working together for 8 hours a day ?
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Total Amount of work completed
Taking man-day-hour we get
9*10*7=630 man-day-hour
Now twice the job as given in question
So 630*2=1260 man-day-hour
Now take day as X
So 1260=8*8X
X=1260/64=>19.68 so 20 days
Time taken to complete job 20 days
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