If 3 moles of NH3 dissociates . Calculate the mass and volume ( at STP ) of N2 and H2 formed ?
Answers
Answered by
1
2NH3 = N2 + 3H2
MASS--
Mole=3
mole=mass given/molar mass
Let mass be x;
mass of N2
3 = x/28
mass=28*3=84g
mass of 3H2-
3 = x/6
x= 18g whereas for H2
3 = x/2
x = 6g
Let volume be v;
for N2-
mole = volume given/volume at S.T.P(22.4L)
3 = v/22.4
v= 67.2 L
for H2-
3 = v/22.4
v = 67.2 L
whereas for 3H2
= 67.2*3
v = 202.6 L
Hope it will help you..
Similar questions