Question

if 3^(n+2)=243 then find the value of 3√n+726

Answer 1

${3}^{n + 2} = 243 \\ = {3}^{n + 2} = {3}^{5}$
Now since the bases are same we can write only exponents
we have
n + 2 = 5
n = 5 - 2
n = 3


Now 3√(3 +726)
=3√729
= 3 × 27
= 81



Hope it helps dear friend ☺️

Answer 2

3^under root n + 726
3^n+2 = 3^5
n+2 = 5
n = 5-2
n= 3
and 3under root n + 726 =
3 under root 3 + 726
= 3 under root 729
= 3*27
= 81