Question

If 3^n = 729, find the value of 3^3n+1

(A) 3^21
(D) 3^15
(B)3^10
(C)3^19​

Answer 1

n = 6

so answer to question is 3^19

Answer 2

Answer:

3^n =729

3^6=729

therefore ,

3^(3×6+1)

3^19