Math, asked by kanchisingh66, 8 months ago

If 3^n = 729, find the value of 3^3n+1

(A) 3^21
(D) 3^15
(B)3^10
(C)3^19

Answers

Answered by tejasshende326

1

n = 6

so answer to question is 3^19

Answered by Anonymous

1

Answer:

3^n =729

3^6=729

therefore ,

3^(3×6+1)

3^19

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