if 3 numbers are in the ratio of 3:2:5 such that sum of their squares is equal to 186 what is the middle number?
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LET THE THREE NUMBERS BE 3x, 2x AND 5x RESPECTIVELY.
THEN,
(3x)²+(2x)²+(5x)² = 186
=> 9x²+4x²+25x² = 186
=> 38 x² = 186
=> x² = 186/38
=> x² = 4.89
=> x = √4.89
HENCE, THE SECOND NUMBER
= 2x
= 2√4.89
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THEN,
(3x)²+(2x)²+(5x)² = 186
=> 9x²+4x²+25x² = 186
=> 38 x² = 186
=> x² = 186/38
=> x² = 4.89
=> x = √4.89
HENCE, THE SECOND NUMBER
= 2x
= 2√4.89
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