Question

If 3(power)x + 64=2(power)6+(√3)(power)8,find the value of x

Answer 1

hi friend,

3(power)x + 64=2(power)6+(√3)(power)8

→3^x+64=2^6+3^4

→3^x+64=64+3^4

subtracting with 64 on both sides

→3^x=3^4

as the bases are equal,powers should be same

→x=4


I hope this will help u ;)

Answer 2

→3^x+64=2^6+√3^8

→3^x+64=64+(√3²)⁴

→3^x=64-64+3⁴

→3^x=3⁴

•Bases are equal. Exponents must be equal.

x=4

Hope it helps