If 3 resistances of 3 ohm each are connected in parallel, what will be their total resistance?
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Inference from the question,
There resistances of 3Ω are connected in parallel
i.e, R1=R2=R3=3Ω
When resistors are connected in parallels their equivalent resistance is found by the expression,
1/Rp =1/R1 + 1/R2 + 1/R3
→1/Rp = 1/3 + 1/3 + 1/3
→1/Rp=3/3
→Rp= 1Ω
The equivalent resistance is 1Ω
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