If 3 resistors of 2 Ω, 7 Ω and 5 Ω are connected in series then what is the total resistance?
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Answer:
0.967 ohm
Explanation:
Given:- Three resistors are connected in parallel
The three resistors are 2, 3, and 5 ohms
Solution:-
Apply the formula of parallel,
1/R=1/R1+1/R2+1/R3
1/R=1/2+1/3+1/5
1/R=15/30+10/30+6/30
1/R=31/30
R=30/31 = 0.967 ohm
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