If 3 resistors of 3 ohm are connected in parallel what will be their total resistance?
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3 resistors of 3ohm
R1= 3ohm
R2=3ohm
R3=3ohm
Therefore 1/Rp=1/R1+1/R2+1/R3
-> 1/Rp=1/3+1/3+1/3
Thus, Rp=3/3=1ohm
[Rp= Total resistance]
R1= 3ohm
R2=3ohm
R3=3ohm
Therefore 1/Rp=1/R1+1/R2+1/R3
-> 1/Rp=1/3+1/3+1/3
Thus, Rp=3/3=1ohm
[Rp= Total resistance]
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