Question

if 3 root a . root b = (x)^1/6, then find x​

Answer 1

Answer:

Given to check whether 3 is a root of the equation

x

2

−4x+3

+

x

2

−9

=

4x

2

−14x+16

Here,

LHS=

x

2

−4x+3

+

x

2

−9

and RHS=

4x

2

−14x+16

Substitute x=3 in LHS

⇒

3

2

−4(3)+3

+

3

2

−9

⇒

9−12+3

+

9−9

⇒

0

+

0

=0

∴LHS=0

Similarly substitute x=3 in RHS

⇒

4(3)

2

−14(3)+16

⇒

4×9−42+16

⇒

36−42+16

⇒

52−42

=

10

∴RHS=

10

Now, we can observe that

LHS



=RHS

∴x=3 is not a solution or root for the equation

x

2

−4x+3

+

x

2

−9

=

4x

2

−14x+16