Math, asked by simransaw, 15 days ago

if 3 sec² x + tan x = 7 then find the value of (cosec 2x +cos x)/( sin 2x +cot x). ​

Answers

Answered by prajithnagasai
0

Step-by-step explanation:

sec²x = 1+tan²x

Substitute in given equation. You get

3tan²x+tanx-4 = 0

By solving this equation, you get

tanx = -1, 4/3

If tanx = -1 → sin2x+cotx is not defined.

So take tanx = 4/3

tanx = 4/3 → secx = 5/3

→ cotx = 3/4 → cosecx = 5/4

→ sinx = 4/5, cosx = 3/5

Substitute the required values in question.

You get 985/1026

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