Question

If 3 sin 0 + 4 cos 0 = 5 then the value of 4 sin 0 - 3 cos s 0
(1) 0
(2) - 1
(3) 1​

Answer 1

Answer:

1) 0

Step-by-step explanation:

3 sinO =5-4cos0

therefore sinO =5-4cosO/4. ..1

put sinO in 4sinO-3cosO=0

therefore cosO=5/7

put cosO in eq 1

sinO =15/28

putting their values in 4sinO-3cosO=0

we get 0