If (3 sin 0+5 cos 0) = 5, prove that (5 sin 0 - 3 cos 6) = plus minus 3.
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Given 3sinθ+5cosθ=5
Let 5sinθ−3cosθ=x
Squre both sides of both the equations :-
⇒9sin² θ+25cos²θ+30sinθcosθ=25 ....Eq1
&
⇒25sin² θ+9cos² θ−30sinθcosθ=x²......Eq2
Adding the equations Eq1 &Eq2 :
⇒34(sin²θ+cos²θ)=25+x²
⇒x²=34−25=9
⇒x=±3
∴5sinθ−3cosθ=±3 (proved)
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