if 3 sinΘ=2 . prove that sin²Θ+cos²Θ=1
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Answer:
3 sino =2
sin o = 2/3
put sino =2/3 in eq.
(2/3)^2 + cos^2= 1
4/9 + (1-sin ^2)= 1( sin^2= 4/9)
4/9+(1-4/9)= 1
4/9+5/9= 1
9/9= 1
LHS = RHS
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